b^2-12b+48=0

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Solution for b^2-12b+48=0 equation:


Simplifying
b2 + -12b + 48 = 0

Reorder the terms:
48 + -12b + b2 = 0

Solving
48 + -12b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-48' to each side of the equation.
48 + -12b + -48 + b2 = 0 + -48

Reorder the terms:
48 + -48 + -12b + b2 = 0 + -48

Combine like terms: 48 + -48 = 0
0 + -12b + b2 = 0 + -48
-12b + b2 = 0 + -48

Combine like terms: 0 + -48 = -48
-12b + b2 = -48

The b term is -12b.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12b + 36 + b2 = -48 + 36

Reorder the terms:
36 + -12b + b2 = -48 + 36

Combine like terms: -48 + 36 = -12
36 + -12b + b2 = -12

Factor a perfect square on the left side:
(b + -6)(b + -6) = -12

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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